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About JG2018

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  1. This is great, thanks for summing that up! So if I wanted to calculate the number of bits that are lost from your example above: Source impedance = 100k; LSb Error = 5LSb; log(5)/log(2) = 2.32 This means that the last 2.32 bits are lost and my ENOB = 9.68?
  2. Hello, the information in this post is by far one of the best I've seen for ADCs! Thank you for passing this information along to others! I have a few questions I hope you could answer.. 1. How did you get the equation to calculate the fractional number of bits [Log(# LSb error)/Log(2)]? 2. For a high impedance input, does the voltage offset due to leakage current contribute to the LSb error? Thanks!
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